Where a lone pair from the nucleophile overlaps With all the sigma* orbital on the leaving team. On the other hand, this phase does not contain the exact same sensitivity to steric hindrance since the SN2 reaction, as we're going to see. Why might this be? After all, shouldn’t the https://edwinoanzk.ampblogs.com/5-simple-techniques-for-solution-bromure-de-potassium-74314981